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--- radar:exercises [2018/06/08 14:29] – iatco
+++ radar:exercises [2026/04/28 15:13] (current) – external edit 127.0.0.1
@@ Line 152: / Line 152: @@
 $SNR_{min}=13\;dB$\\  \\
 **Solution**\\
-We can compute the power received using the deterministic radar equation\\
+We can compute the power received using the deterministic radar equation:
 \begin{equation}
 P_r=\frac{P_t\;G^2\;\lambda^2\;RCS}{(4\pi)^3\;D^4}
-\end{equation}\\
+\end{equation}
 where $\lambda=c/f_0=0.23\;m$\\
 To compute $P_r$ is better to use the dB method:\\
@@ Line 172: / Line 172: @@
 \begin{equation}
 P_r\simeq-139.3\;dBW=-109.3\;dBm=1.17\times10^{-11}\;mW
-\end{equation}\\
+\end{equation}
-In order to compute the maximum range we assume that the system temperature has been taken at the antenna exit and also we assume a total losses equal to 1 (no losses).\\
+In order to compute the maximum range we assume that the system temperature has been taken at the antenna exit and also we assume a total losses equal to 1 (no losses).
 \begin{equation}
 R_{max}^4=\frac{P_t\;G^2\;\lambda^2\;RCS}{(4\pi)^3\;S_{min}^4}
@@ Line 353: / Line 353: @@
 <caption>Increase of the SNR in order to detect a fluctuating target respect to a fixed targe. [(cite:TTR)]</caption>
 </figure>
-As we can see in the Figure {{ref>sw1_2}} for SW1 and SW2 and a $P_D=0.9$ it's necessary to increase the minimum signal to noise ratio of 7.5 dB, so now $SNR_{min,SW1/2}=20.7\;dB$. Changing now the $SNR_{min}$ in Table {{ref>tab3}} the maximum range is:\\
+As we can see in the Figure {{ref>sw1_2}} for SW1 and SW2 and a $P_D=0.9$ it's necessary to increase the minimum signal to noise ratio of 7.5 dB, so now $SNR_{min,SW1/2}=20.7\;dB$. Changing now the $SNR_{min}$ in Table {{ref>tab3}} the maximum range is:
 \begin{equation}
 R_{max}=49.68\;dBmeters=92.9\;Km